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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: again function . this time IITJEE 1997
Forum Index -> Differential Calculus like the article? email it to a friend.  
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pratikanand (574)

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the graph of the function cosxcos(x+2)-cos^2(x+1)is
 
 
a) a straight line passing through (0, -sin^2 1) with slope 2
 
 
b) a straight line passing thru (0,0)
 
c) a parabola with vertex (0, -sin^2 1)
 
 
d) a straight line passing thru the point (pi/2, -sin^2 1) and parallel to x axis

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rhd92781 (686)

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cosxcos(x+2) - cos^2(x+1)
= 1/2 (cos(2x+2) + cos 2) - cos^2(x+1)
= 1/2(2cos^2(x+1) - 1) + cos2/2 - cos^2(x+1)
= - (1-cos2)/2
= -sin^2(1)
so y=-sin^2(1)
its a straight line passing through (x, -sin^2(1)) parallel to x-axis
is it correct?

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

I am only one,
But still I am one.
I cannot do everything,
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And because I cannot do everything
I will not refuse to do the something that I can do.
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rhd92781 (686)

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do u know d ans??

<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Animated Letters</DIV></TD></TR></TABLE>

I am only one,
But still I am one.
I cannot do everything,
But still I can do something;
And because I cannot do everything
I will not refuse to do the something that I can do.
- Edward Everett Hale
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pratikanand (574)

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D is the answer n u r right,,,

Woods are lovely dark and deep
But i have promises to keep
And miles to go before i sleep
And miles to go before i sleep

" HAVE A NICE DAY "






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