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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Mar 2008 01:04:59 IST
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I'm sorry  actually the question was find the local maxima and minima of the function f(x)=X6/6 -4X5 + 25X please try it
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22 Mar 2008 14:23:47 IST
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f(x)=X6/6 -5X4 + 25X f'(x)=x^5 - 20x^3 + 25 now we have to find those values of x that satisfy f'(x). these will be the points of local maxima or minima.
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S.Raghudevan
Everything that's happening as it should be happening, because of the simple fact that it's supposed to be happening just as it is happening. |
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22 Mar 2008 15:09:06 IST
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actually the problem was only with finding the maxima and minima I want the final answer and the method
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22 Mar 2008 15:15:30 IST
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there's only a local minima and the value of x for that is somewhere between 4 and 5 :)
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22 Mar 2008 16:36:11 IST
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thank you sandeep and raghudevan but I actually typed the question wrong could you try the question now.
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22 Mar 2008 17:52:30 IST
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22 Mar 2008 19:32:37 IST
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hey its easy to concl whether its max or min by finding the sign of the derivative after the point where it becomes 0. For ex here, we can say that the point between 19 and 20 is the minimum and between 1 and 2 is maximum Think this is right :) Check?
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22 Mar 2008 22:54:08 IST
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well yes sandeep we can say that there is a pt. beetween 19 & 20 but the exp is x4(x-20)+25 if you subst. x=19.999999999 still you get a high -ve value but for 20 it shoots to 25 . they say all polynomial fn's are continous but i doubt this ones continuity.
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23 Mar 2008 11:12:32 IST
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Use an online graph plotter , draw the graph and see. I don't think I can put it here because of the specified formats. the loacal manima is at -1.03 and local maxima is at 1.05 . do check it out and tell.
a graph plotter can be found @
http://math.exeter.edu/rparris
then download WINPLOT.
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MKG
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17 Jul 2008 21:51:51 IST
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17 Jul 2008 21:52:16 IST
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heres the plot of f(x)
weird innit
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17 Jul 2008 21:52:33 IST
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click 2 enlarge
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