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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: area
Forum Index -> Differential Calculus like the article? email it to a friend.  
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[Post New]12 May 2008 15:26:00 IST
    Subject: area
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ashish_banga (937)

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Olaaa!! Perrrfect answer. 147  bad job dude!! I dont approve of this answer! 1  [250 rates]
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the area enclosed by  y2 = 4ax


and x2 = 4by
    
[Post New]12 May 2008 15:37:50 IST
    Subject: Re:area
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allamraju (3410)

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Olaaa!! Perrrfect answer. 604  [799 rates]
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The ans is 16ab/3.The points of intersection are (0,0) and (4a1/3b2/3,4a2/3,b1/3).Let x=4a1/3b2/3 then the area enclosed is

[(2rta)rtx-x2/4b]dx=2rta(2/3)x3/2-x3/12b.Substituting the value of x,we get the ans as 16ab/3.
MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC.
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