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Differential Calculus
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venkat v.t
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Joined: 7 Aug 2007
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9 Sep 2007 13:26:18 IST
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Equation of tangent at t=0 us x-2y=0.
Sol) f1(0)=
[ t]
[ 0] {2t+t2Sin(1/t)-0}/t =2+0=2
[ 0] {2t+t2Sin(1/t)-0}/t =2+0=2 g1(0)=
[ t]
[ 0] (1/t)Sint2/t =1
[ 0] (1/t)Sint2/t =1Therefore slope of tangent at t=0 to the given curve is g1(0)/f1(0)=1/2.
The point of contact is (0,0) {given in the problem}
So by using point-slope form the tangent is x-2y=0.
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0 and 0 if t=0







