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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 May 2008 23:07:28 IST
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d range of d function
f(x)= sin (xe[x] + x2-x) x (-1,infinity)
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its time fr u to achive d goal wake up donot hesitate to do hard work |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 13:00:42 IST
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MY SALUTES TO THOSE WHO ANSWERS
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its time fr u to achive d goal wake up donot hesitate to do hard work |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 13:05:19 IST
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Is the answer [-1,1]
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 20:27:20 IST
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giveme d answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 20:28:58 IST
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giveme d answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 20:30:49 IST
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giveme d answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 May 2008 20:40:00 IST
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The domain of sinx is R and range is [-1,1].For the given function,for x in (-1,infinity),it takes only +ve values and sinx is positive for x in [0,pi] and -ve in [pi,2pi] and periodic.So,I think the ans is [-1,1].
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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