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Ask iit jee aieee pet cbse icse state board experts Expert Question: differential calculus
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kasirajan.1990 (1084)

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  find dy/dx of the following 1) xy=e(x-y)
                                       2) find the derivative of function given by:
                                          (1+x) (1+x2) (1+x4) (1+x8) and hence find f'(1)
    
utkarsh123 (219)

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rate me then i will tell

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neeraj_agarwal_1990 (887)

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1) x dy/dx + y= e^(x-y) . (1- dy/dx)
now u can solve

2) 1+ x+ x^2 + x^4 + x^8 + x^15
now u can solve
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subs (79)

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1 >>>> (e^x[x-1])/(x^2(e^y+ye^y))



2>>>>1+2x+4x^3+8x^7+15x^14

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vinod (1433)

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kasirajan.1990  solution for the frst quen ..
 
EDITED


Science is vision multiplied!



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vinod (1433)

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kasirajan.1990  solution for the second quen .. plzz tell me some thing is wrong
 
f1= 2 x 2 x 2 x 2 [ 1/2 + 2/2 + 4/2 + 8/2 ]
  
= 16 x [7.5]
 
= 120 .
 
 
 


Science is vision multiplied!



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vasanth (2315)

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dy/dx = (1 + x.x)(1+x.x.x.x)(1+x.x....8times)       +(1+x)( 2x)(1+x^4)(1+x^8)  + (1+x)(1+x^2)(4x^3)(1+x^8)  +  (1+x)(1+x^2)(1+x^4)(8x^7) 
 
 
x = 1
 
dy/dx = 8 + 16 + 32 + 64 = 120
 
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Arjun (812)

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hiiiiiiii.........
 
now for da second question.........
 
f(x) = (1+x)(1+x2)(1+x4)(1+x8)
 
f(x)=1/1-x *(1-x)(1+x)(1+x2)(1+x4)(1+x8)
 
u'll get a+b*a-b=a2-b2form........go on simplifyin.......
 
finally.......u'll get
 
f(x)=1-x16/1-x
 
d/dx=1-x(-16x15)-(-1)/(1-x)2
 
 
the differential is equal to......
 
(1-x)(-16x15)+1/(1-x)2
 
here f'(1)does not exist bcoz......in da denominateor u get 0..........
 
hope u got it!!!!
 
 
 
 
 
 

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Arjun (812)

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hey.......i guess m gettin a wrong answer.........but da method is ryt,na??????????????


plzzzzzzzzzzzzz help!!!!!!

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Arjun (812)

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ne body.help.........

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vinod (1433)

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The mthod is absolutely right !! and fast and easy tooooo....but i toooo am wondering y itz giving wrong ans

Science is vision multiplied!



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amar.gupta (590)

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Dear,

I think you have got the ans. of both of your question.

however vinod , you have done a slight mistake while solving the que.1 .

it should be (dy/dx)[(1+y)/y] =(x-1)/x


and arjun as you have multiplied and divided by (x-1) but you can divide the expression by (x-1) only when x can not be 1 . but here x can be 1 .

that's why you have find this kind of expression in the end .

it is not defined at x=1 but the results will be true for all other x.

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vinod (1433)

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Thank u sir,
 
I have edited the post ..

Science is vision multiplied!



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ananya.123 (0)

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second answer is 130??