Problem) If y = log(x/a+bx)^x,prove that x^3 d^2y/dx^2=(x dy/dx-y)^2
Solution) y = log(x/a+bx)x = x log(x/a+bx)
or dy/dx = log(x/a+bx) + 1
and d2y/d2x = (1/a + b) /(x/a+bx)
so x3 d2y/d2x = x2 (x/a+bx)/(x/a+bx) = x2 ...........(1)
Now, (x dy/dx-y) = x [log(x/a+bx) + 1] - x log(x/a+bx)
or (x dy/dx-y) = x
or (x dy/dx-y)2 = x2 ................(2)
Hence from eq. (1) and (2)
x3 d2y/d2x = (x dy/dx-y)2 , hence proved.