IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

ruhana

cos inverse of ( 4x³/27 -x)

prateekdhariwal

see cos inverse ka differenciation is 1/^{[ ]}

1-x²

^{putting x=4x^3/27-x...and differentiating 4x^3/27-x and solve ull get the answer!!!!!}

^{Rate if req!!!}

uday_zingtudor

cos^-1(4x³ - 3x) = 3cos^-1x

Using this u get the given expression as

3cos^-1x/3

Now differentiating this u get

3(1/rt(1-x²/9) = 9/rt(9-x²)

~Cheerio!!!

ruhana

hey pratik i'm not dumb i know how to sole differential equtions...............................i wanted the answer neways ur method will end up giving huge expressions nothing else....

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