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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jul 2007 19:42:26 IST
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can u differentiate log(log(|sin x|)) for all values of x.justify your answer?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jul 2007 19:55:26 IST
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ans::cosx/log|sinx| |sinx|
this ans is invalid for x=90 and x=0; for x=90 =>log sinx=0 and for x=0=> sinx=0; rate please
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trying to reach higher than the highest but with controlled ambition |
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first find the domain of the given function
f(x)=log{log(|sin(x)|)}
as sin(x) belongs to [-1,1] so {log|sin(x)|} is defined for all x except when sinx=0. as inside the log the value of sinx will vary frm 0 to 1 so log|sinx| will be a -ve number and log(-ve number) is not defined.
so,
the given function is not defined for any value of x. So it cannot be differentiated.
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~ANSHUMAN
I was born intellegent, education ruined me. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Jul 2007 20:52:50 IST
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0<= |sinx| <= 1
Hence log(|sinx|) < 0
log{log(|sinx|)} is not defined for any value of x.
Hence it is a non-differentiable function.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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