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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Nov 2006 10:48:08 IST
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find differentiation of f(x)= log mod x
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If Knowledge is power then .. God Am I . |
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16 Nov 2006 12:29:48 IST
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There is same Qs in arihant differentials. d/dx of log mod X = 1/mod X * d/dx of mod X
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16 Nov 2006 14:54:54 IST
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answer should be 1/mod X
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17 Nov 2006 12:33:29 IST
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y=log|x| dy/dx = (1 / |x|) (|x| / x) = 1/ x
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17 Nov 2006 12:53:45 IST
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Sir I am not able to get ,why have you multiplied mod X/X?
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17 Nov 2006 12:55:42 IST
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Am I Ignoring any rule or formula sir?
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17 Nov 2006 21:07:17 IST
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If y = |x| then dy / dx = |x| / x therefore if y = log |x| then dy / dx = (1/ |x|) mulitplied by differentiation of |x| which is nothing but |x| / x. Therefore the answer is 1 / x
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17 Nov 2006 21:08:33 IST
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The answer is 1 / x.
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27 Jan 2007 19:03:19 IST
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log modx can always be differntiated as logx as the domain of logarihmic function is all positive real and mod x is always positive d/dx(log modx)=1/x
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25 Feb 2008 14:09:36 IST
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log mod x. log of -ve quantities is not possible so log mod x =log x diff log x=1/x.
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