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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Apr 2008 16:10:27 IST
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Find the domain y= cos-1(1-lxl) /2
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21 Apr 2008 16:25:11 IST
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x= {-1} ?
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I Tried So Hard And Got So Far
But In The End
It Doesnt Even Matter... |
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21 Apr 2008 17:05:26 IST
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Find the domain y= root [ cos-1(1-lxl) /2]
First cos-1(1-lxl) /2 >= 0 as it is under root
cos-1(1-lxl) >= 0
0 >= 1 - |x| >= 1
|x| E [0, 1]
x E [-1, 1]
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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21 Apr 2008 17:06:32 IST
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ummmmmm.....CONFUSION
is denominator 2 inside the arc cos enclosure? or is the denominator for the whole thing?
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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21 Apr 2008 23:09:59 IST
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2 is inside cos-1 n ans given is [-3 3] not sure with it though
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21 Apr 2008 23:27:16 IST
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well then sboosy is perfectly correct :)
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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21 Apr 2008 23:35:47 IST
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spidery u need not have the condition cos-1(1-lxl) /2 >= 0
bcos cos inverse lise beetween 0 to pi any way. so the condition is only for the part inside the cos inverse as sboosy has done.
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21 Apr 2008 23:53:56 IST
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no harm done anyway :)
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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21 Apr 2008 23:54:18 IST
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the thing is , i took 2 as the denominator to the whole thing
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
* Your friendly neighborhood spideyunlimited |
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