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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Find the sum using only calculus
Forum Index -> Differential Calculus like the article? email it to a friend.  
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sunnyguha (9)

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Olaaa!! Perrrfect answer. 1  [3 rates]

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1.--                     


2.--                         |x|<1


 


PLz guys I need these to be solved only by calcus, will rate all those who answer.


THnx am waiting


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ramkumar_november (1266)

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Olaaa!! Perrrfect answer. 230  [288 rates]

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for the first problem the required sum is.....


S =  1+2x+3x^2+4x^3+.....+nx^{n-1}


now consider


T =  x+x^2+x^3+x^4+....+x^n


using sum of GP formula


T = x+x^2+x^3+x^4+....+x^n  =    \frac{x(x^n-1)}{x-1}


now find \frac{dT}{dx}  which will give you S


 

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zorro (106)

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Olaaa!! Perrrfect answer. 18  [26 rates]

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for second one..

consider the series

S = x + 2x^2 + 3x^3 + 4x^4 ----------- infinity
its an AGP, solve to get

x + 2x^2 + 3x^3 + 4x^4 ----------- infinity = x/(1-x)^2

differentiate both sides

1 + 2^2.x + 3^2.x^2 + 4^.x^3----------infinity = d/dx[x/(1-x)^2]

see, LHS is what u want

now solve RHS to get ur answer

cheers !





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