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shinee (220)

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 f(a)=g(a)=k, then the nth derivatives of fn (a) ,gn (a)exist and are not equal for some n
if
[ x]a ] f(a)g(x)-f(a)-g(a)f(x)+g(a)/g(x)-f(x) =4, then he value of k is

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ayshwarya (241)

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dude is it 4 actually d procedure is
limx->a k g(x)-k-k f(x)+k/g(x)-f(x)=4
limx-.a k[g(x)-f(x)]/g(x)-f(x)=4 hence as k is constant limx->a k=k
hence k=4
rate me if im writ plz
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ayshwarya (241)

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isnt it writ ive done everything correctly plz reply me fast
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ayshwarya (241)

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hey yaaron wats wrong in my answer do u think any mistakeve i comitted
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