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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: function
Forum Index -> Differential Calculus like the article? email it to a friend.  
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ashish_banga (937)

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let the function


)


be defined on the interval [0 ,1] . the odd extension of F(x) on the interval [ -1 , 1 ] is

    
ashish_banga (937)

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anyone here
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spideyunlimited (3083)

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G(x) = { - F(-x) -1<= x < 0
{ F(x) 0<= x <= 1

where G(x) is the odd extension .... I just had to look up on the net about odd extensions.

WHERE
- F(-x) = - [ -4sinx + 3cosx + log (|x| + sqrt ( 1 + x^2 ) ]
= 4 sin x - 3 cos x - log (|x| + sqrt (1 + x^2) ]



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