IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

abhijeet_0201

statement 1:the domain of the function f(x) = 1/

([cosx]-[sinx]) where[] represents greatest integer func is [2npi - pi/2,2npi]

statement 2:a function f(x)=1/g(x) is well defined in domain of g(x) if g(x) is non zero

what shud be the ans (A) OR(B)

elastiboysai

A

coz c g(x) is defined for all x in 4th quad

also gvn expln is rt.

g is non zero in gvn domain so dat f can b defnd(gvn dom subset of g's domain)

elastiboysai

abhijeet_0201

man but g(X) shud also be positive too(not only non zero)

chetan_kp

definitely right answer is A coz in 2nd statement they have asked the domain of g(x); for that we have to subject g(x) i.e. g(x) = 1/f(x); so g(x) can be zero
plz nudge if wrong

abhijeet_0201

what my doubt is that shud not g(x) also be +ve other than being non zero????????

elastiboysai

read the question carefully

g(x)is root.([cosx]-[sinx]).

watevers in the root is pos. in 4th quad man.

so das domain of g.

now B says " f is well defined in domain of g" if..

so dere dey have already taken care of g's domain.

deir statement 1 takes care dat g is defined, so was da prob

abhijeet_0201

okay thanks ............didnt read carefully!!!!!

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