Split the integral as 12 f'(x)dx +223 f'(x)dx + 3 34 f'(x)dx and so on till (a-1)a-1a f'(x)dx. => f(2)-f(1) + 2[f(3)-f(2)] + 3[f(4)-f(3)] +4[f(5)-f(4)] and so on till (a-1)[f(a)-f(a-1)] => -[f(1)+f(2)+f(3)+....+f(a-1)] + (a-1)f(a) Can you make the options more clearer???
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