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![[Post New]](/templates/default/images/icon_minipost_new.gif) 31 May 2007 23:36:26 IST
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if f(x)={1 when x Q} and f(x)={0 when x Q}, then draw the graph for htis function.
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I think we can't draw the graph!
(there lies an irrational b/w two rational numbers) and (one rational b/w two irrational numbers)
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1 Jun 2007 12:10:56 IST
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ya we cant because of the above reason and thats 100% rite
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2 Jun 2007 11:42:22 IST
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i think the graph will not be continues and break at 0 and rest graph will be of constant function.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
   
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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2 Jun 2007 11:48:01 IST
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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2 Jun 2007 16:27:06 IST
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U will have to find a rational no. to plot a graph...u can find it ..eg. 1.
now what will be the next point??
irrational or rational??
u can draw graph specifically for some points but that will not be a continuous graph.
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