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Differential Calculus

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19 Sep 2007 16:53:33 IST

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Functions -TMH IIT-JEE

None

The Period of the function f(x) = cosec²3x + cot4x is

(a)

/3 (b)

(c)

/6 (d)

Soln.

Period of cosec²3x is pie/3

and period of cot4x is pie/4

and their (pie/3,pie/4) l.c.m is 7pie/12

but there is no such option.

(The question is from TMH IIT-JEE 2007

Chapter -Functions ,Page-21.6 and Example-6)

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Comments (1)

Krishna Gopal Singh

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Joined: 29 Dec 2006

Posts: 5153

20 Sep 2007 00:47:13 IST

Like 1 people liked this

You don't have to find lcm. You have to find smallest numbers m and n such that m*pi/3 = n*pi/4. And answer is (4,3)
In this case period is pi

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