IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

utkarsh_kus

how to find the fundamental period of::

f(x)=f(-x+9)

&

f(x)=f(2x+11)

Plz help soon....

spideyunlimited

fundamental period is that which when added to x in f(x) will give f(x) again

example.. sin (x + 2pi) = sin(x) so fundamental period is 2 pi

here in 1) f(x) = f(-x+9)
to get -x + 9 we add 9 - 2x to x
f( x + (9-2x) ) = f ( -x + 9 ) which is equal to f(x) as given ..

thus fundamental period is 9 - 2x here

in 2) f(x) = f(2x + 11)
like in above case here we add (x + 11) to x to get (2x + 11)
thus fundamental period is (x + 11)

PS. plz rate

joyfrancis

I think the two functions are constant functions , they will not have any period.

spideyunlimited

oh my god @joy... wht has happened to u ... were given that f(x) value is repeated when we substitute x by (- x + 9)
sin also has the same thing
x gives same as x+2pi

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