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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Sep 2007 17:11:06 IST
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If f(x) is continuous function x belongs to R and the range of f(x) is (2, 26) and g(x)=[f(x)/c] is continuous in x belongs to R then the least positive integral value of c( [] denotes greatest integer function) a) 2 b)3 c)5 d)6
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Sep 2007 17:24:38 IST
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6
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its easier to crack jee than 2 crack cet. |
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Answer is D As f(x) is continous and belongs to 2 to 26^1/2 values of 2,3,5 makes f(x)/c greater than 1 hence discontinouity will occur u cn see it as [ (2,26^1/2)/c] if c is 2 , 3 or 5 g(x) will b greater than 1 and become discontinous so if we take as 6 ,f(x)/c will b less than 1 and answer will be g(x)=0 which will b continous for all f(x) belongs (2,26^1/2)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Sep 2007 17:24:57 IST
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Answer is D As f(x) is continous and belongs to 2 to 26^1/2 values of 2,3,5 makes f(x)/c greater than 1 hence discontinouity will occur u cn see it as [ (2,26^1/2)/c] if c is 2 , 3 or 5 g(x) will b greater than 1 and become discontinous so if we take as 6 ,f(x)/c will b less than 1 and answer will be g(x)=0 which will b continous for all f(x) belongs (2,26^1/2) plz rate
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Sep 2007 01:25:37 IST
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lolz.........yeah guyz the answer is 6 only.......they have all explained it b4 i got my chnace...............
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