hii ram
see
clearly f(x) is a perodic func with peroid 2 pie
so the diffrence between the graetest and least values of the func f(x) is the diffrence between grtest nd least values on the interval [0, 2 pie]
we have
f'(x) = - (sin x + sin2x - sin3x )
= -( 2 sin3x/2 cosx/2 - 2 sin3x/2 cos 3x/2 )
= - 4 sinx/2 sin3x/2 sinx
so f'(x) = 0 so x= 0, 2pie /3 , pie and 2pie
now f(0) = 1 +1/2 - 1/3 = 7/6
f(2pie/3)= -13/12
f(pie)= - 1/6
f(2pie)- 7/6
the largest and smallest of these values are 7/6 and - 13/ 12
so diffrence = 9/4
correct me if m rong