IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

ayshwarya

d/dx {(x²ⁿ-1)/(x²ⁿ-1)} = ?

allamraju

Plz check the question,bcoz the num & den are same.so,ans is 0.

ayshwarya

na frnd its not 0 bcoz d nr & dr r not same

ayshwarya

oh sorry im rong d quesn is in nr its '--' & '+' in dr

shinee

x^(2n-1)/x^(2n+1)
[(2n-1)(x)^(2n-2)(x^(2n+1)) -(2n+1)(x)^(2n)(x)^(2n-1)]/[x^4n+2]
[(2n-1)x^(2n-2+2n+1)-(2n+1)x^(2n-1+2n)]/[x^4n+2]
[(2n-1)x^(4n-1)-(2n+1)x^(4n-1)]/[x^4n+2]
-2x^(4n-1)/[x^4n+2]
-2x^(4n-1-4n-2)
-2x^(-3)

risin

$\frac{{x}^{2n}-1}{{x}^{2n}+1}=1-\frac{2}{{x}^{2n}+1}Now,differentiate..$ this might be simpler.

shinee

oh, sorry , i have taken whole (2n-1) and (2n+1) in the power
ok, differentiating 1-2/(x^2n +1)
we get, 0-(-2n(x)^(2n-1)2/(x^2n+1)^2

amulye

i 2 got d same ans but was shokd 2 c d ans as x^2n+1 in dr plz try it

shinee

it is (x^2n+1)^2 in the dr

amulye

na noy to d power of 2 but 1

amulye

plz atleast giv d hints

allamraju

Ask & Discuss Questions with Community & Experts

Plz check the question,bcoz the num & den are same.so,ans is 0.

Write it as risin said and differentiate,ans is 4nx^2n-1/(x²ⁿ+1)²

Ask & Discuss Questions with Community & Experts

Plz check the question,bcoz the num & den are same.so,ans is 0.

Write it as risin said and differentiate,ans is 4nx2n-1/(x2n+1)2

Write it as risin said and differentiate,ans is 4nx^2n-1/(x²ⁿ+1)²