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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Mar 2008 20:27:09 IST
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if periodic, find its period.
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2008 00:23:12 IST
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f(x) is a constant fuction.so it is periodic whiose period is indeterminate>.............
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2008 21:26:07 IST
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pls explain !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Mar 2008 21:28:45 IST
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'a' is a constant right?? if so, f(a+x) = f(2a) implies f(x) = f(2a) also.. implies constant function.. whose fundamental period is indeterminate..
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 20:44:40 IST
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f(a+x) = f(2a) implies f(x) = f(2a) i didnt get it pls explain !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 21:22:33 IST
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f(a+x) = f(2a) is an identity...so we can put any value of x...
put x-->x-a.. so f(x) =f(2a) which means its constant.....i saw a question in which a constant function was marked as periodic...
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 22:14:39 IST
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yes f(x) is a constant function......
the speciality about constant function is that it is the only function which is periodic without any fundamental period.........
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 09:18:24 IST
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see f(a+x) is a constant f(2a) as for any value for x it has a constant value f(2a) see for a constant function f(x)=k consider a T which is such that f(T+x)=f(x) but as f(x+ anything)=the same constant thus there is no definite period it is undefined understood???
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 09:19:01 IST
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period can be any value so no fundamental period
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