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![[Post New]](/templates/default/images/icon_minipost_new.gif) 24 Nov 2007 20:47:01 IST
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The image of the interval [ -1,3] under the mapping f(x)= 4x3 - 12x is -??? Ans- [-8,72] Please explain me the question and provide answer wid solution. Don't worry about the rates.
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yaar you simply have to find the interval in which the values lie , if we put x in interval [-1,3],
f'(x) = 12x^2 -12 { being a polynomial f(x) always continuous+differentiable}
f'(x) = 0 { getting the min and max values}
x^2 -1 =0
x= +1,-1
thus we have to check the values of f(x) at -1,1,3 to get the image
f(-1) = 8
f(1) = -8
f(3) = 72
thus image of interval [-1,3] under mapping f(x) = 4x^3 -12x is
[-8,72] answer....
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25 Nov 2007 23:15:36 IST
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Thanx nishant.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
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