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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 May 2007 12:02:59 IST
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if f(x) is continous over closed interval [a,b] and it is increasing at all pts in [a,b] except at 1 pt where it is not differentiable (sharp edge in the graph). then it is right to say that f(x) is non decreasing in [a,b].
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SAARE JAHAAN SE ACHCHA;
GOIIT HAMARA!!!!!!!!!!!!!!!!!!!!!!!!! |
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22 May 2007 12:11:05 IST
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hiiiiiiii.
nope u don say tat it is decreasin but u say it is not continous...
and even if u want to mention if it is increasin or decreasin then u can split the intervals n say it is inc frm a 2 p and frm p 2 b...
another case(jus to explain)
and instd of being discontnous at tat point, if f(x)dec, then u say it is strictly increasin till tat pt.. n at tat point u hav a maxima..
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Moderation Team
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