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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 16:23:07 IST
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If f(x)= (x-a)(x-b)(x-c)..............................................(x-z) then find the value of f'(x)=?
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AJIT |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 16:25:23 IST
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take log on both sides and differentiate. That shud do.
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The clock on the wall ticking away... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 16:33:55 IST
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answer is very easy it is 0 am i right yeah i am suer it is right
dont forget to rate me
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you are in the competition to beat the competition
you work hard for a desired result |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 17:05:39 IST
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can u give the detail?
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AJIT |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 18:46:48 IST
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f(x)=(x-a) (x-b)......(x-x)...(x-z) =(x-a) (x-b)......0...(x-z) =0
since 0 is a constant f `(x)=0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 20:26:10 IST
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i think rates were assured..
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you are in the competition to beat the competition
you work hard for a desired result |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Sep 2007 23:41:05 IST
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Good answer ambreesh, but poor question ajitres. This is more like playing tricks then a genuin differentiation question
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Sep 2007 16:24:21 IST
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there will be on term with (x-x) so the whole thing will become 0. and diff. of a constant is 0.
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 21 Sep 2007 23:17:44 IST
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ans is zero as (x-x)=0 f(x)=0 f'(x)=0
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