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Ask iit jee aieee pet cbse icse state board experts Expert Question: Interesting ques. on differentiation rates assured
Forum Index -> Differential Calculus like the article? email it to a friend.  
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Ajitres (29)

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If  f(x)= (x-a)(x-b)(x-c)..............................................(x-z)
then find the value of
f'(x)=?

AJIT
    
dip_xaverian (117)

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take log on both sides and differentiate. That shud do.

The clock on the wall ticking away...
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ambareesh13 (226)

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answer is very easy
it is 0
am i right yeah i am suer it is right

dont forget to rate me

you are in the competition to beat the competition
you work hard for a desired result
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Ajitres (29)

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can u give the detail?

AJIT
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nadeemoidu (1184)

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f(x)=(x-a) (x-b)......(x-x)...(x-z)
    =(x-a) (x-b)......0...(x-z)
    =0

since 0 is a constant f `(x)=0
   
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ambareesh13 (226)

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i think rates were assured..

you are in the competition to beat the competition
you work hard for a desired result
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krishna.gopal (2149)

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Good answer ambreesh, but poor question ajitres. This is more like playing tricks then a genuin differentiation question

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
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spideyunlimited (3083)

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there will be on term with (x-x) so the whole thing will become 0.
and diff. of a constant is 0.


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rtiit (431)

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ans is zero as (x-x)=0
f(x)=0
f'(x)=0
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