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Differential Calculus
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21 Aug 2008 22:59:25 IST
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No it is NOT periodic.
@shanaditya..........
if the period was 1 then f(x) would've been equal to f(x+1) for ALL x ....i.e. sin[x] = sin[x+1]
But this fails at at least one point x=1/2.
At x=1/2,we get
sin[0.5] = sin [1.5]
sin0 = sin1
0 = sin1.........which is absurd.
22 Aug 2008 15:08:07 IST
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@coolguy_2008
The function is f(x)= sin[x] where [.] denotes the greatest integer function!
It is NOT sinx.
f(x)=f(x+2
) is true for sinx but not for sin[x].
For sin[x],
at x=0,
f(x)= sin[0] = 0.
f(x+2
)= sin[0+2
] = sin[6.28] = sin6 which is not equal to 0!!
25 Aug 2008 22:13:24 IST
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you jst hav to sketch the graph of sin x, and u''ll see that IT REPEATS AFTER AN INTERVAL OF 2n PIE.
arey its an understood fact that 30 degree is same as (360+30)degree, which goes on every time you complete on revolution around the origin. the values repeat...............................
I CAN BET ON THAT
rate me if i'm right, as i alwaz am
arey its an understood fact that 30 degree is same as (360+30)degree, which goes on every time you complete on revolution around the origin. the values repeat...............................
I CAN BET ON THAT
rate me if i'm right, as i alwaz am







]=sin[x+2
.









NO