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Differential Calculus

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Joined: 1 Dec 2006
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22 Sep 2007 10:20:07 IST
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L'hospitals rule
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what is this L'hospitals rule and lebinetz rule?


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Priyesh's Avatar

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Joined: 18 Feb 2007
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22 Sep 2007 10:37:08 IST
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l'Hôpital's rule states that for functions f(x) and g(x), if:
lim_{x 	o c}f(x)=lim_{x 	o c}g(x)=0,
or:
lim_{x 	o c}f(x)=lim_{x 	o c}g(x)=pminfty,
then:
lim_{x	o c}rac{f(x)}{g(x)} = lim_{x	o c}rac{f'(x)}{g'(x)}
where the prime (') denotes the derivative.   For this rule to hold, the limit lim_{x	o c}rac{f'(x)}{g'(x)} must exist or else we again apply L'hopital rule again if possible.
Priyesh's Avatar

Blazing goIITian

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22 Sep 2007 10:41:09 IST
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Leibniz's rule for differentiation under the integral sign, named after Gottfried Leibniz, tells us that if we have an integral of the form
 \int_{y_0}^{y_1} f(x, y) \,dy
then for x \in (x_0, x_1) the derivative of this integral is thus expressible
 {d\over dx}\, \int_{y_0}^{y_1} f(x, y) \,dy = \int_{y_0}^{y_1} {\partial \over \partial x} f(x,y)\,dy
provided that f and \partial f / \partial x are both continuous over a region in the form
[x_0,x_1]\times[y_0,y_1].
Alternate form
 
For a monovariant function g:
 {d\over dx}\, \int_{f_1(x)}^{f_2(x)} g(t) \,dt = g(f_2(x)) {f_2'(x)} -  g(f_1(x)) f_1'(x)
Or
 {d\over dq}\, \int_{a(q)}^{b(q)} g(t,q) \,dt = g(b(q),q) {b'(q)} -  g(a(q),q) a'(q) + \int_{a(q)}^{b(q)} {\partial \over \partial q}  g(t,q) \,dt
 
 



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