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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 10:52:48 IST
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during periodicity
in some cases we have to find the lcm
can anyone tell me how to do it???
for ex - lcm of pie/2 and pie/3 is pie
how???????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 11:46:17 IST
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come on no one is answering
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 11:46:35 IST
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is no one willing to help me
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 12:28:34 IST
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m(pi/2)=n(pi/3) acc. to LCM definition,hence (n/m)=3/2 so least value of n and m can be n=3 and m =2,hence we get LCM as pi.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 12:37:00 IST
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ok then how is lcm of [ 2pie/3 , pie/6 , pie/12 ] = 2pie/3
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jun 2008 14:45:17 IST
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U must try to understand from the name Least Common Multiple only.If l.c.m of a group of no.s is k,then each no. in the group shud give k by multiplying by a suitable +ve integer.
In case of 2pi/3,pi/6,pi/12,If l.c.m is k then
k=m(2pi/3)=n(pi/6)=p(pi/12)
2m=n/2=p/4
m=n/4=p/8.
So,the least values of m,n,p are 1,4,8 and l.c.m is k=2pi/3.
Hope u got it.
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MAKING A MISTAKE IS HUMAN BUT REPEATING IT IS IDIOTIC. |
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