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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 00:47:18 IST
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[n ] [ ] {(n-3)/3}n/2
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"If u win u need not have to explain and if u lose thn u should not be there to explain"
-Adolf Hitler |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 09:14:54 IST
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help yaarrrrrrrrrrrrr
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"If u win u need not have to explain and if u lose thn u should not be there to explain"
-Adolf Hitler |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 09:31:42 IST
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Is the answer 0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 09:39:19 IST
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edited
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 09:43:44 IST
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[ n] [ ] e^[{n-3}/3-1]xn/3 now try nudge me if incorrect
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 17:58:32 IST
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the answer is not zero raulrag and i didnt understood effort can u explain it in detail
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"If u win u need not have to explain and if u lose thn u should not be there to explain"
-Adolf Hitler |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 18:05:27 IST
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Hey man i went wrong in one of my steps
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 18:06:10 IST
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what is the answer anywayzzzz
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 18:11:38 IST
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The limit does not exist at all !!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 18:48:36 IST
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n inifnity {(n-3)/3}n/2
n-3 / 3 + 1 -1 = 1 + (n-6)/3
so
lim = n --> inf { 1 + (n-6)/3)}^(n/2)
= en/2 * (n-6)/3
= infinity
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~ANSHUMAN
I was born intellegent, education ruined me. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 19:27:52 IST
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THE ANSWER IN THE BOOK IS 1/e^3/2
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"If u win u need not have to explain and if u lose thn u should not be there to explain"
-Adolf Hitler |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 20:16:38 IST
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Are you sure that the limit tends to ?
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__________________________________________________________________________________________________________
From J.R.R. Tolkien's 'The Lord of the Rings':
All that is gold does not glitter
Not all who wander are lost
The old that is strong does not wither,
Deep roots are not reached by frost.
From ashes a fire shall be woken
From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 21:10:56 IST
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if it is 1/e^(3/2) then pls recheck the question....
even the graph says that the limit will be infinity
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~ANSHUMAN
I was born intellegent, education ruined me. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 22:28:50 IST
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it is infinity by direct method u can place value of x as infinity check whether u have typed correct Q
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jan 2008 22:28:53 IST
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ya the limit tends to infinity i think their is a printing mistake in d answer but anyways can u tell what is the limit if the answer coming e^3/2
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"If u win u need not have to explain and if u lose thn u should not be there to explain"
-Adolf Hitler |
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