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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Limit of a sequence
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hsbhatt (5794)

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\text {Define a sequence as follows:} \\ \\

a_n = \frac {1} {10^{n^2}}} \\ \\

\text{Is} \ \lim_{n \to \infty} \sum_{n=1}^\infty \frac {1} {10^{n^2}} \ \text {a rational number?}

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computer001 (1849)

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bhatt sir isnt it sigma(1 to n) where n tends to infinity

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sandeepramesh (1247)

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i dont get why it shouldnt be rational maybe
 
Bcos the summation is done over rational terms only right? Then why shouldnt the sum be rational only?
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amaron (726)

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What is given is a non recurring,non terminating decimal .
Hence not a rational number.

Note that sum of infinite rational terms need not be rational.

ex = 1 +x +x2 /2! ....

is obviously not rational even for rational values of x.

That solves the problem!

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sandeepramesh (1247)

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Is that so mr bhatt
 
but i think its only lim n----> infinity  n not infinity itself so its still a finite number of terms making it rational maybe
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hsbhatt (5794)

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nice work amaron.

I mixed it up a little, it is of course a sum to infinite terms.

If you write it down it looks like 0.100100001..., this is a non-terminating, non-recurring decimal representation, which is typical of an irrational number

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sandeepramesh (1247)

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oh yes nice :)
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hsbhatt (5794)

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I simplified the question a bit. The original one had a +ve integer k instead of 10.

Then too the result hold, for in base k, it will read 0.100100001...

I thought it was a lovely concept to bring here

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