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 Community Discussion Question:
Limits
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 May 2007 16:27:55 IST
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Could somebody give me the formula of trigonometry required to solve LIMITS .... :)
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2 May 2007 16:55:24 IST
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[x ] [ 0] ( sin x ) / x =1 same as with tan and its reciprocals all are equal to 1
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2 May 2007 17:00:30 IST
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try to make the function of trigo as same as in denominator by using addition, mutiplication subtraction or division in both numerator and denominator. but the best way to solve most of the trigo questions is to use l' hopital rule.
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2 May 2007 19:39:46 IST
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look everyone says 1 but it is actually not correct
Lt x~0(Sin x)/x=.999999........ just less than 1 when we take [(sin x0/x]=0 where []represents greatest integer functiojn
similarly Ltx~0 (tan x)/x=1.0000000000000....1...... just greater than 1
[tanx/x]=1
the actual geometric inequality being
Sinx
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2 May 2007 19:40:43 IST
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plz rate the ans
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2 May 2007 21:30:43 IST
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1 - cos x = 2 sin^2 x/2
1 + cos x = 2 cos^2 x/2
Two formulae which are kinda important if u dont know them already...ill try to punch more in if i find time
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