IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

agnit_thebest

(limit x tends to -2) (tan

x)/(x+2)

sachin_gupta1991

lim ( tan pi(x+2) - 2pi )/ (x+2)

lim tan pi(x+2) - tan 2pi/1+ tan2pi(tan pi(x+2))

As tan 2pi is zero,

lim tan pi(x+2) x pi

-------------------------

pi(x+2)

Thus,

(limit x tends to -2) (tan

x)/(x+2) = pi

Plzz rate me if I am correct.

nunoxic

x tends to -2
let x = -2 +h
h will tend to 0

substitute

u will get,
l = tan (pi (-2 + h) ) / h
= tan (-2pi + pi h) / h=
tan pi h / h
= pi

Rate If Useful

(this can also be done by L Hospital.......but u shud try and avoid it when other methods are possible)

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