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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Mar 2008 22:38:39 IST
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f(x)=sin{pie[x-pie]}/(1+[x]square)
then discuss the continuity and the differentiability of f(x).
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28 Mar 2008 22:45:52 IST
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does [] denote greatest integer function??
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Ajay Antony |
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28 Mar 2008 22:53:02 IST
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yes
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28 Mar 2008 23:00:51 IST
Accepted Answer [?]
![[Up]](/templates/default/images/icon_up.gif)
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cont. and diff. everywhere.........because f(x) = 0 for all x
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28 Mar 2008 23:06:08 IST
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i agree with lokeshsardana the num=0 as it is reduced to sin n where n is an int and denomintor will never become zero as it is a sqr fn .Hence f(x)=0 for all x.
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Ajay Antony |
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28 Mar 2008 23:06:44 IST
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can u plz xplain??
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28 Mar 2008 23:22:02 IST
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see let [x-pie] be any integer then [x-pie]pie will be of the form of n(pie) where n belongs to I but sin(n(pie) is always zero and denominator is always a positive value greater than 1 and thus the whole value is 0 and whether the n takes the value k or k-1 sin(k(pie))=0 and sin(k-1(pie))=0 and thus is continuous and differentiable everywhere!!!!
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