| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Apr 2008 12:04:30 IST
|
|
|
find (lim x--> 0) [(e1/x - 1) / (1/x)]
|
There is no better feeling in this world than being a winner! |
|
|
|
11 Apr 2008 12:06:13 IST
|
|
|
is the question x[e^1/x -1] in the limit as x tends to zero?? the question is not clear...
|
"I a universe of atoms.......an atom in the universe" |
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 12:11:29 IST
|
|
|
yea!!
|
There is no better feeling in this world than being a winner! |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 12:30:37 IST
|
|
|
answer is 1
put 1/x=h
|
Chat with ankur khurana |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 12:47:51 IST
|
|
|
limit x=>0 e raised to something - 1/something is always 1.answer will b 1 my dear!!!.......Rate if needed...
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 12:57:27 IST
|
|
|
LHL is not equal to RHL
so limit does not exist
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 13:09:21 IST
|
|
|
The answer is 1
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 13:10:03 IST
|
|
|
no ashish banga ...the answer is one ,,,,....
|
_________________________
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 13:35:57 IST
|
|
|
answer will be 1 if the exponent of e and denominator tend to 0.....
here it is infinity...
try the series expansion of e^x n u will find that limit tend to +infinity in 1 side
n minus infinity other...
thus limit does not exist...
|
iitdreams came true!!
Second year student
Department of electronics..
IIT Kharagpur. |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
11 Apr 2008 13:37:46 IST
|
|
|
yes the same thinking i got
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
12 Apr 2008 23:34:22 IST
|
|
|
lim ex-1/x = 1..........................................(standard result)
x-->0
so the answer is 1
|
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
 |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
12 Apr 2008 23:38:42 IST
|
|
|
limit does not exist as the answer in coming out to be infinity
|
    
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
15 Apr 2008 18:22:00 IST
|
|
|
lt (e^1/x-1)x=1only when x tends to infinity not zero. so here the ans is lt doesnot exist since lt n rt limit tends to -infinityn +infinity
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
1
