IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

aditi_g

im getting 11e/24
just use the series expansion of (1+1/x)^x

rishabh29288

answer shud be 11e/24
(1+1/x)^1/x=e-e/2x+11e/24x^2........
use this and u shall get the answer

thedumbheadwithnobrain

how did u get this expansion,,,is it general form acheived from Mclaren series

rishabh29288

well if u want to derive any kind of expansion u can use macclaurin-taylor series but at this stage it is better to learn certain standard expansions.........if u r still interested then i will tell how its done,its not that difficult actually
The Taylor series of a real or complex function f(x) that is infinitely differentiable in a neighborhood of a real or complex number a, is the power series

f(a) + f'(a)/1! +f''(a)(x-a)^2/2! + and so on

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