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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Jun 2008 19:16:58 IST
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Evaluate:lim [ 1+nth root{1^n +2^n} + nth root{2^n+3^n} + .......................+nth root{(m-1)^n +m^n}]
where m,n approach infinity.......
Sorry couldnt write in proper way becoz new to me.........
plzzz help ASAP
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IIT!!!!!!!!!!!!! I am coming................... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2008 16:17:40 IST
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help..................
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IIT!!!!!!!!!!!!! I am coming................... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 29 Jun 2008 07:41:57 IST
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Take the larger of the two no.s in the series outside the root. So equation becomes
1+ 2 * nth root {1 +(1/2)^n} + 3 * nth root {1 + (2/3)^n}...................m * nth root {1 + (m-1/m)^n}
Lim n->inf = 1+2 + 3....+m
= m(m+1)/2
Lim m-> inf gives the answer infinity. Is it right?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jun 2008 11:56:44 IST
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NO...........
answer is 1/2
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 30 Jun 2008 12:44:39 IST
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Srry about my solution then, I did have a doubt in that. I will get back to you with a solution ASAP. But its strange that the answer is less than 1. :\
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Let us learn to dream, gentlemen, and then perhaps we shall learn the truth.
- August Kekule |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jul 2008 08:41:09 IST
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What you actually needed was something else so my answer is right but to know what you needed see this: http://www.artofproblemsolving.com/Forum/viewtopic.php?t=212489
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