| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Apr 2007 21:25:29 IST
|
|
|
Evaluate:
[n] [infinity] { 1/2(tan x/2) + 1/22 (tan x/22) + 1/23(tan x/23).......1/2n(tan x/2n)}
[ans: 1/x - cotx]
|
|
|
|
4 Apr 2007 22:02:48 IST
|
|
|
i dunno the answer to dis deadly question ,but tell me ,is it objective ??
|
light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 11:41:45 IST
|
|
|
no its not objective...
|
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 14:00:54 IST
|
|
|
[n] [infinity] { 1/2(tan x/2) + 1/2 2 (tan x/2 2) + 1/2 3(tan x/2 3).......1/2 n(tan x/2 n)} Adding and subtracting 1/2ncotx/2n Now, We know that cotx-tanx=2cot2x Here, - 1/2ncotx/2n+1/2ntanx/2n = -1/2n-1cotx/2n-1 Doing thus all the way in the problem, we get left with [ n][infinity ] - cotx +1/2 ncotx/2 n = - cotx +[ n][ infinity] 1/2 ncotx/2 n = - cotx + 1/x { On applying the limits} = 1/x - cotx ~Cheerio!!!!!
|
Talk less work more!! {To be simplistic and 2 gain respect}
Eat less work more!!! {To "build" ur body}
Work less Do more!!! {2 make ur life big}
don't get scared !!!
 |
this reply: 17 points
(with 3
in 4 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 17:42:35 IST
|
|
|
How did u solve that uday??
|
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 17:49:29 IST
|
|
|
i'm editing the post
|
Talk less work more!! {To be simplistic and 2 gain respect}
Eat less work more!!! {To "build" ur body}
Work less Do more!!! {2 make ur life big}
don't get scared !!!
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 18:14:41 IST
|
|
|
Got it man..
I just dont realise when to use that identity cotx-tanx=2cot2x
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
5 Apr 2007 19:10:18 IST
|
|
|
Well done Uday.
|
Sudeep Kumar
(B tech, IITd)
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
