Use L-Hopitals - cos x - sin x - 1/ [1-x] by 3x^2 sin x - cos x - 1/[1-x]^2 by 6x cos x + sin x - 2 / [1-x]^3 by 6 Substitute Values 1 + 0 - 2 by 6 -1 / 6
I May Have Been Wrong......Please Temme If I Am
Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute
Use L-Hopitals - cos x - sin x - 1/ [1-x] by 3x^2 sin x - cos x - 1/[1-x]^2 by 6x cos x + sin x - 2 / [1-x]^3 by 6 Substitute Values 1 + 0 - 2 by 6 -1 / 6
I May Have Been Wrong......Please Temme If I Am
Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute
The expression is not rigthly written it should be
lim [ 1-sinx+cosx+log(1-x) ] / x3
x0
Just apply L-hospitals rule to derive the value of the limit, it comes out to be -1/6
The Scientist does not study nature because it is useful; he studies it because he delights in it, & he delights in it because it is beautiful. If nature were not beautiful, it would not be worth knowing, life would not be worth living. Ofcourse I do not here speak of that beauty that strikes the senses, the beauty of qualities & appearances; not that I undervalue such beauty, far from it, but it has nothing to do with science; I mean that profounder beauty which comes from the harmoniuos order of the parts, & which a pure intelligence can grasp.
Moderation Team
![[Post New]](/templates/default/images/icon_minipost_new.gif){kind=icon}
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
0
+cos
0
