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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Mar 2008 13:17:15 IST
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[x ] [ 0] [(a+x^n)^1/m - a^1/m]/[g(x)]^n
where g(x) = x or sinx or tanx or sinhx or tanhx or sin^-1x or tan^-1 x or tanh^-1x or sinh^-1 x
u can take anyone as g(x)
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Talk less work more!! {To be simplistic and 2 gain respect}
Eat less work more!!! {To "build" ur body}
Work less Do more!!! {2 make ur life big}
don't get scared !!!
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27 Mar 2008 13:37:15 IST
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is it
1/m a^[ (1-m)/ m ]
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27 Mar 2008 13:45:48 IST
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I think that is right but I want the procedure man.
I too got the same answer!!!
edit: okay done!! i've got it
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Talk less work more!! {To be simplistic and 2 gain respect}
Eat less work more!!! {To "build" ur body}
Work less Do more!!! {2 make ur life big}
don't get scared !!!
|
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in 0 votes ) [?]
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