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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Nov 2007 20:25:47 IST
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[ x] [0 ] (1- cos x)/ x
solve it plz..!!
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25 Nov 2007 20:27:03 IST
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Is the answer 0 ??
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My birthday is no ordinary day.
Its the day when i declared in my own voice,
I WILL NOT GO QUIETLY INTO THE NIGHT,
I WILL NOT VANISH WITHOUT A FIGHT,
I AM GOING TO LIVE ON,
I AM GOING TO SURVIVE,
I AM GOING TO GET WHATEVER I WANT.
I CELEBRATE MY BIRTHDAY, AS MY INDEPENDENCE DAY !!!!!!!!! |
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25 Nov 2007 20:28:21 IST
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0/0 form.. apply l'hospital's rule..
so limit= sinx = 0... for x=>0
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Keep working....................Iam comming..
your's only,
Success!! |
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25 Nov 2007 20:28:55 IST
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differentiate numerator and deno,
it cums to be sin x and value of sin 0 shld be 0
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25 Nov 2007 20:35:47 IST
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its lim(x->0) 2sin^2x/x
= lim(x->0) 2 (sinx/x)^2 * x
=lim(x->0) 2x =0
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25 Nov 2007 20:36:25 IST
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it can be done easily without any use of L-Hopital rule ie lim x->0((sinx/2)2x/2)/(x/2)2 =0(Ans) Anupam
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