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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Mar 2008 09:24:37 IST
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fnd max area of an isosceles trngle inscrbd in an ellipse wid 1 vertx on d major axis......my prob is how to find d ht???
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19 Mar 2008 13:39:37 IST
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one vertex is on the major axis. due to symmetry, we can assume for max area, the vertex common to the 2 equal sides of the isoceles triangle lies on (a,0) of tyhe ellipse x^2/a^2 + y^2/b^2 = 1 where a>b
now, the other 2 vertices will be (-acos@, bsin@) and (-acos@,-bsin@)
therfore, the height of the triangle = (a +acos@)
and base = 2bsin@
find area and difftiate wrt @
:)
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19 Mar 2008 20:00:00 IST
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http://www.goiit.com/posts/list/differenciation-simple-ncert-q-47390.htm#235601
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