THE QUESTION HAS BEEN ANSWERED WITHOUT USING ANY SPECIAL METHODS. I JUST CIRCULATED THROUGH THE COMMON TYPE OF FUNCTIONS:
1. POLYNOMIAL
2. TRIGONOMETRIC
3. LOGARITHMIC
4. EXPONENTIAL etc....... SO THAT THE GIVEN CONDITIONS ARE SATISFIED............
THEREFORE
f (x) = - [ log ( x - a + 1 ) ] 2n + m + b where 'm' is any even natural number.
f (x) = - ( x - a )2n + m + b where 'm' is any even natural number.