IIT JEE , AIEEE Forum - Mathematics , Differential Calculus - on finding limit of trig functions when x-->y is not equal to zero

toshi

question:
lim

--

cos inverse of x
x--> --1 --------------------------------------- ?

x+1

krish

In ur question , if we apply L hospitals Rule of 0/0 form.....

we get _x

_-1 (1/

cos^-1x) .( 1/

1-x²) / (1/

(x+1))

Cancelling out certain terms from numerator and denominator and applying limits , we get 1/

(2

)

plz reply if i am wrong..........

krishna.gopal

Right answer Krish