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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: OPEN CHALLENGE!
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[Post New]10 Jun 2007 13:45:22 IST
    Subject: OPEN CHALLENGE!
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murtuza (0)

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lim  ( 1 +  a1/x +(a+1)1/x+........(a+n-2)1/x) x
x0
 
 
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[Post New]10 Jun 2007 13:51:18 IST
    Subject: OPEN CHALLENGE!
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shubham_sachdeva (1876)

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it is 1. just put value of x u willl get
(blah + blah + (blah)^ infinity....................) ^ 0

which is 1....

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[Post New]10 Jun 2007 14:42:20 IST
    Subject: Re: OPEN CHALLENGE!
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him26.89 (207)

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it can be written as
 
[t ][infinity]  [ 1+ at............................+(a+ (n-2))t]1/t
 
{a + (n-2)} [1/{a+(n-2)}t + ...............+ 1]1/t
 
= a+(n-2)
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