IIT JEE , AIEEE Forum - Mathematics , Differential Calculus - solve this as soon as possible.i need it immediately

shikhar.jain50

the value of function

(where[.]denote greatest integert function)

kashish123453

ans is 1 i think....

separate x^2 into xmultiply by x....
then x->0 [ x/sinx multiply x/tanx].....
=[1*1] = [1] =1

shikhar.jain50

answer given by kashish is wrong by every inch
he has voileted the basic rules of limit by doing partial replacement of the limit
partial replacement should not be done unless all factors have finite limit
and greatest integer function is a non continous function
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please clear your basic and than answer

Anshul007

According to Second order approximation Sinx=X- /6

TanX=X+/3

Limit goes like this

sorry for typing mistake, numerator is x square

and denominator >numerator

Therefore answer is ZERO

DEEPAK.DKV

sinx=x-x^3/3!

tanx=x+x^3/3

putting this value &by solving we get

[1/1+3/18*x^2+x^4/18]=0

as value of numerotor less than denominatorans=0

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the value of function

(where[.]denote greatest integert function)