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Differential Calculus
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richa sharma
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Joined: 7 Nov 2007
Posts: 91
19 Mar 2008 12:36:28 IST
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by [], do u mean the GIF?
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19 Mar 2008 12:40:14 IST
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Here is the solution......
f(x) = x3 , x>0
-x3 , x<0
find LHD and RHD at x=0
both will be equal so it is differentiable
f ' (x) = 3x2 , x>0
-3x2 , x<0
now for f ' (x) find LHD and RHD at x=0
both will be equal so f ' (x) is differentiable ....
f '' (x) = 6x , x>0
-6x , x<0
so f '' (x) exists for all real x and it is
f '' (x) = 6x , x>0
-6x , x<0
clear with my solution??













