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Community Discussion Question:
prove
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2008 00:07:19 IST
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Prove that every odd continuous function has its value at x=0
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2008 01:09:17 IST
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take xample like sinx ,or....x^3 these r odd functions their value at x=0 is 0
so u can prove that bt in general ..can't help...
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don't walk as if u rule d world
walk as if u dont care who rules d world
-this is knw as attitude
B who u r and say wat u feel ......
coz those who mind don't matter ........
and those who matter dont mind ......... :)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jun 2008 01:52:53 IST
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For odd functions f(x) = - f(-x)
at x = 0 2f(0) = 0 f(0) = 0
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- Gaurav Ragtah (spideyunlimited)
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this reply: 7 points
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