IIT JEE , AIEEE Forum - Mathematics , Differential Calculus

vidur99

how is x mod(x) a strictly inc. funcn in (-1,1) wont derivatve be 0 at x=0

johri_anshuman

just make the graph. the function is strictly increasing in (-1,1) and it is also differential as there is no peak in the graph.

f(x)=x^2 when x>=0
f(x)=-x^2 when x<0.

deepak_agarwal

when x>0 then xmod(x) becomes x^2

and when x<0 then x mod(x) becomes x^2 as well....so this makes xmod(x)=x^2 at all instants...draw the graph of x^2 and you find that it is increasing

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