|x|^{x*x - x-2} <1

i have somehow got the answers but the problem is with the concepts ..i cant understand the concepts.......????

CAN ANY ONE SOLVE AND EXPLAIN IT TO ME>>>salutes for them..

I think there is something wrong in the question,put x=1 or 2,the ans is 1 and u gave it to be less than 1.Plz check the question.

Erm well here is my solution:

Take log base 10 both sides to get (x^2 -x -2)log|x| <0

Case 1: |x|<1

x^2 -x -2 >0

Case 2 |x|>1

x^2-x-2 <0

Solve both equations and get the set.

Oh..I didn't see the question well.I thought that we need to prove that for all x.Sorry for my mistake.Anyway conjurer is right I think.

Continuing with conjurer,For case1,there is no soln.For case 2,The soln is x(1,2).

Hence the ans is x(1,2)

For the product to be -ve,one of them shud be -ve and the other +ve.The log fun. is +ve when IxI>1 and is -ve when IxI<1.So,we proceeded like that.Hope u understood.